3^x^2(1/27)^x=9^x-2

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Solution for 3^x^2(1/27)^x=9^x-2 equation: 



3^x^2(1/27)^x=9^x-2

We move all terms to the left:

3^x^2(1/27)^x-(9^x-2)=0



Domain of the equation: 27)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3^x^2(+1/27)^x-(9^x-2)=0

We get rid of parentheses

3^x^2(+1/27)^x-9^x+2=0

We multiply all the terms by the denominator


3^x^2(+1-9^x*27)^x+2*27)^x=0

Wy multiply elements

3^x^2(+1-9^x*27)^x+54x=0

We add all the numbers together, and all the variables

54x+3^x^2(+1-9^x*27)^x=0

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